Difference between revisions of "TriangleCurve Command"
From GeoGebra Manual
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:creates implicit polynomial, whose equation in [[w:Barycentric_coordinate_system_(mathematics)|barycentric coordinates]] with respect to points A,B,C is given by the fourth parameter. | :creates implicit polynomial, whose equation in [[w:Barycentric_coordinate_system_(mathematics)|barycentric coordinates]] with respect to points A,B,C is given by the fourth parameter. | ||
− | {{Example|1=<code>TriangleCurve[P,Q,R,(A-B)*(B-C)*(C-A)=0] </code> gives a cubic curve consisting of perpendicular bisectors of all the segments PQ, QR, RP.}} | + | {{Example|1=If ''P,Q,R'' are points, <code>TriangleCurve[P,Q,R,(A-B)*(B-C)*(C-A)=0]</code> gives a cubic curve consisting of perpendicular bisectors of all the segments ''PQ, QR, RP''.}} |
{{Note|The first three points can be called A,B or C, but in this case you cannot use e.g. x(A) in the equation, because A is interpreted as the barycentric coordinate.}} | {{Note|The first three points can be called A,B or C, but in this case you cannot use e.g. x(A) in the equation, because A is interpreted as the barycentric coordinate.}} |
Revision as of 01:38, 5 February 2012
- TriangleCurve[<Point A>,<Point B>,<Point C>,<Equation in A,B,C>]
- creates implicit polynomial, whose equation in barycentric coordinates with respect to points A,B,C is given by the fourth parameter.
Example: If P,Q,R are points,
TriangleCurve[P,Q,R,(A-B)*(B-C)*(C-A)=0]
gives a cubic curve consisting of perpendicular bisectors of all the segments PQ, QR, RP.
Note: The first three points can be called A,B or C, but in this case you cannot use e.g. x(A) in the equation, because A is interpreted as the barycentric coordinate.