Difference between revisions of "ConjugateDiameter Command"
From GeoGebra Manual
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− | <noinclude>{{Manual Page|version= | + | <noinclude>{{Manual Page|version=5.0}}</noinclude>{{command|conic}} |
− | {{command|conic}} | + | ;ConjugateDiameter( <Line>, <Conic> ):Returns the ([w:Conjugate diameters|conjugate diameter)] of the diameter that is parallel to the given line (relative to the conic section). |
− | ;ConjugateDiameter | + | :{{Example|1=<code>ConjugateDiameter(-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0)</code> yields line 5''x'' + 16''y'' = 11}} |
− | :{{Example|1=<code>ConjugateDiameter | + | |
− | ; ConjugateDiameter | + | ; ConjugateDiameter( <Vector>, <Conic> ):Returns the ([w:Conjugate diameters|conjugate diameter)] of the diameter that is parallel to the given vector (relative to the conic section). |
− | :{{Example|1=Let ''u'' = (4,1) be a vector. Then <code>ConjugateDiameter | + | :{{Example|1=Let ''u'' = (4,1) be a vector. Then <code>ConjugateDiameter(u, x^2 + 4 y^2 + 2x - 8y + 1 = 0)</code> yields line ''x'' + ''y'' = 0}} |
Latest revision as of 17:15, 7 October 2017
- ConjugateDiameter( <Line>, <Conic> )
- Returns the ([w:Conjugate diameters|conjugate diameter)] of the diameter that is parallel to the given line (relative to the conic section).
- Example:
ConjugateDiameter(-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0)
yields line 5x + 16y = 11
- ConjugateDiameter( <Vector>, <Conic> )
- Returns the ([w:Conjugate diameters|conjugate diameter)] of the diameter that is parallel to the given vector (relative to the conic section).
- Example: Let u = (4,1) be a vector. Then
ConjugateDiameter(u, x^2 + 4 y^2 + 2x - 8y + 1 = 0)
yields line x + y = 0