Difference between revisions of "Invert Command"

From GeoGebra Manual
Jump to: navigation, search
(→‎CAS Syntax: modified math visualization as in CAS View)
Line 32: Line 32:
 
:{{note|1=<div>The function must contain just one ''x'' and no account is taken of domain or range, for example for f(x)=x^2 or f(x) = sin(x). If there is more than one ''x'' in the function another command might help you:</div>
 
:{{note|1=<div>The function must contain just one ''x'' and no account is taken of domain or range, for example for f(x)=x^2 or f(x) = sin(x). If there is more than one ''x'' in the function another command might help you:</div>
 
::{{example|1=<div>Both <code><nowiki>Invert[PartialFractions[(x + 1) / (x + 2)]]</nowiki></code> and <code><nowiki>Invert[CompleteSquare[x^2 + 2 x + 1]]</nowiki></code> yield the inverse functions.</div>}}}}
 
::{{example|1=<div>Both <code><nowiki>Invert[PartialFractions[(x + 1) / (x + 2)]]</nowiki></code> and <code><nowiki>Invert[CompleteSquare[x^2 + 2 x + 1]]</nowiki></code> yield the inverse functions.</div>}}}}
 +
 +
:{{note|1=<div>In the [[CAS_View|CAS View]], the following also work: <code><nowiki>Invert[(x + 1) / (x + 2)]</nowiki></code> and <code><nowiki>Invert[x^2 + 2 x + 1]</nowiki></code></div>}}

Revision as of 14:17, 19 September 2012


Invert[ <Matrix> ]
Inverts the given matrix.
Example:
Invert[{{1, 2}, {3, 4}}] yields

\begin{pmatrix} -2 & 1\\ 1.5 & -0.5 \end{pmatrix} , the inverse matrix of

\begin{pmatrix} 1 & 2\\ 3 & 4 \end{pmatrix}

.

CAS Syntax

Invert[ <Matrix> ]
Inverts the given matrix.
Example:
Invert[{{a, b}, {c, d}}] yields

\begin{pmatrix} \frac{d}{ad- bc} & \frac{-b}{ad- bc}\\ \frac{-c}{ad- bc}& \frac{a}{ ad- bc} \end{pmatrix} , the inverse matrix of

\begin{pmatrix} a & b\\ c & d \end{pmatrix}

.
Invert[ <Function> ]
Gives the inverse of the function.
Note:
The function must contain just one x and no account is taken of domain or range, for example for f(x)=x^2 or f(x) = sin(x). If there is more than one x in the function another command might help you:
Example:
Both Invert[PartialFractions[(x + 1) / (x + 2)]] and Invert[CompleteSquare[x^2 + 2 x + 1]] yield the inverse functions.
Note:
In the CAS View, the following also work: Invert[(x + 1) / (x + 2)] and Invert[x^2 + 2 x + 1]
© 2024 International GeoGebra Institute