Difference between revisions of "ConjugateDiameter Command"

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;ConjugateDiameter[ <Line>, <Conic> ]:Returns the diameter of the conic section being its [[w:Conjugate diameters|conjugate diameter]] parallel to the line.
 
;ConjugateDiameter[ <Line>, <Conic> ]:Returns the diameter of the conic section being its [[w:Conjugate diameters|conjugate diameter]] parallel to the line.
 
:{{Example|1=<code>ConjugateDiameter[-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0]</code> yields line 5''x'' + 16''y'' = 11}}
 
:{{Example|1=<code>ConjugateDiameter[-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0]</code> yields line 5''x'' + 16''y'' = 11}}
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; ConjugateDiameter[ <Vector>, <Conic> ]:Returns the conjugate diameter of the diameter that is parallel to the vector (relative to the conic section).
 
; ConjugateDiameter[ <Vector>, <Conic> ]:Returns the conjugate diameter of the diameter that is parallel to the vector (relative to the conic section).
 
:{{Example|1=Let ''u'' = (4,1) be a vector. Then <code>ConjugateDiameter[u, x^2 + 4 y^2 + 2x - 8y + 1 = 0]</code> yields line ''x'' + ''y'' = 0}}
 
:{{Example|1=Let ''u'' = (4,1) be a vector. Then <code>ConjugateDiameter[u, x^2 + 4 y^2 + 2x - 8y + 1 = 0]</code> yields line ''x'' + ''y'' = 0}}

Revision as of 11:21, 8 July 2013



ConjugateDiameter[ <Line>, <Conic> ]
Returns the diameter of the conic section being its conjugate diameter parallel to the line.
Example: ConjugateDiameter[-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0] yields line 5x + 16y = 11


ConjugateDiameter[ <Vector>, <Conic> ]
Returns the conjugate diameter of the diameter that is parallel to the vector (relative to the conic section).
Example: Let u = (4,1) be a vector. Then ConjugateDiameter[u, x^2 + 4 y^2 + 2x - 8y + 1 = 0] yields line x + y = 0
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