Difference between revisions of "Comments:Bavarian Final Exam 2012 Analysis I"
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{{CAS Example|title=Oil Example|level=example|meta=Bayrische Abituraufgabe|type=Analysis|subtype=I|year=2012}} | {{CAS Example|title=Oil Example|level=example|meta=Bayrische Abituraufgabe|type=Analysis|subtype=I|year=2012}} | ||
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Test content - English version | Test content - English version | ||
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;Mod[ <Integer a>, <Integer b> ] | ;Mod[ <Integer a>, <Integer b> ] | ||
:Yields the remainder when integer ''a'' is divided by integer ''b''. | :Yields the remainder when integer ''a'' is divided by integer ''b''. | ||
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:{{example|1=<div><code><nowiki>Mod[x^3 + x^2 + x + 6, x^2 - 3]</nowiki></code> yields ''4 x + 9''.</div>}} | :{{example|1=<div><code><nowiki>Mod[x^3 + x^2 + x + 6, x^2 - 3]</nowiki></code> yields ''4 x + 9''.</div>}} | ||
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Latest revision as of 19:13, 11 May 2013
CAS Examples: Oil Example
Oil Example
Categories for CAS Examples (All CAS Examples)
Examples from Bavarian Final Exams
By type
By year
de:Bayrische Abitur 2012 Analysis I
Test content - English version
- Mod[ <Integer a>, <Integer b> ]
- Yields the remainder when integer a is divided by integer b.
- Example:
Mod[9, 4]yields 1.
- Mod[ <Polynomial>, <Polynomial>]
- Yields the remainder when the first entered polynomial is divided by the second polynomial.
- Example:
Mod[x^3 + x^2 + x + 6, x^2 - 3]yields 4 x + 9.
CAS Syntax
- Mod[ <Integer a>, <Integer b> ]
- Yields the remainder when integer a is divided by integer b.
- Example:
Mod[9, 4]yields 1.
- Mod[ <Polynomial>, <Polynomial> ]
- Yields the remainder when the first entered polynomial is divided by the second polynomial.
- Example:
Mod[x^3 + x^2 + x + 6, x^2 - 3]yields 4 x + 9.
