Difference between revisions of "BinomialDist Command"

From GeoGebra Manual
Jump to: navigation, search
Line 27: Line 27:
 
:*<code><nowiki>BinomialDist[3, 0.9, 3, false]</nowiki></code> yields ''<math>\frac{729}{1000}</math>'', the probability of all three packets being transferred successfully.
 
:*<code><nowiki>BinomialDist[3, 0.9, 3, false]</nowiki></code> yields ''<math>\frac{729}{1000}</math>'', the probability of all three packets being transferred successfully.
 
:*<code><nowiki>BinomialDist[3, 0.9, 0, true]</nowiki></code> yields ''<math>\frac{1}{1000}</math>'', the probability of none of the three packets being transferred successfully,
 
:*<code><nowiki>BinomialDist[3, 0.9, 0, true]</nowiki></code> yields ''<math>\frac{1}{1000}</math>'', the probability of none of the three packets being transferred successfully,
:*<code><nowiki>BinomialDist[3, 0.9, 1, true]</nowiki></code> yields ''<math>\frac{7}{250}</math>'', the probability of at topmost one of three packets being transferred successfully,
+
:*<code><nowiki>BinomialDist[3, 0.9, 1, true]</nowiki></code> yields ''<math>\frac{7}{250}</math>'', the probability of at most one of three packets being transferred successfully,
:*<code><nowiki>BinomialDist[3, 0.9, 2, true]</nowiki></code> yields ''<math>\frac{271}{1000}</math>'', the probability of at topmost two of three packets being transferred successfully,
+
:*<code><nowiki>BinomialDist[3, 0.9, 2, true]</nowiki></code> yields ''<math>\frac{271}{1000}</math>'', the probability of at most two of three packets being transferred successfully,
:*<code><nowiki>BinomialDist[3, 0.9, 3, true]</nowiki></code> yields ''1'', the probability of at topmost three of three packets being transferred successfully.
+
:*<code><nowiki>BinomialDist[3, 0.9, 3, true]</nowiki></code> yields ''1'', the probability of at most three of three packets being transferred successfully.
 
:*<code><nowiki>BinomialDist[3, 0.9, 4, false]</nowiki></code> yields ''0'', the probability of exactly four of three packets being transferred successfully,
 
:*<code><nowiki>BinomialDist[3, 0.9, 4, false]</nowiki></code> yields ''0'', the probability of exactly four of three packets being transferred successfully,
:*<code><nowiki>BinomialDist[3, 0.9, 4, true]</nowiki></code> yields ''1'', the probability of at topmost four of three packets being transferred successfully.</div>}}
+
:*<code><nowiki>BinomialDist[3, 0.9, 4, true]</nowiki></code> yields ''1'', the probability of at most four of three packets being transferred successfully.</div>}}

Revision as of 09:54, 10 September 2011



BinomialDist[ <Number of Trials>, <Probability of Success> ]
Returns a bar graph of a Binomial distribution.
Parameters:
Number of Trials: number of independent Bernoulli trials
Probability of Success: probability of success in one trial
BinomialDist[ <Number of Trials>, <Probability of Success>, <Boolean Cumulative> ]
Returns a bar graph of a Binomial distribution when Cumulative = false.
Returns a bar graph of a cumulative Binomial distribution when Cumulative = true.
First two parameters are same as above.
BinomialDist[ <Number of Trials>, <Probability of Success>, <Variable Value v>, <Boolean Cumulative> ]
Let X be a Binomial random variable.
Returns P( X = v) when Cumulative = false.
Returns P( X ≤ v) when Cumulative = true.
First two parameters are same as above.

CAS Specific Syntax

In CAS View only one syntax is allowed:

BinomialDist[ <Number of Trials>, <Probability of Success>, <Variable Value v>, <Boolean Cumulative> ]
Let X be a Binomial random variable.
Returns P( X = v) when Cumulative = false.
Returns P( X ≤ v) when Cumulative = true.
Example:
Assume transfering three packets of data over a faulty line. The chance an arbitrary packet transfered over this line becomes corrupted is \frac{1}{10}, hence the propability of transfering an arbitrary packet successfully is \frac{9}{10}.
  • BinomialDist[3, 0.9, 0, false] yields \frac{1}{1000}, the probability of none of the three packets being transferred successfully,
  • BinomialDist[3, 0.9, 1, false] yields \frac{27}{1000}, the probability of exactly one of three packets being transferred successfully,
  • BinomialDist[3, 0.9, 2, false] yields \frac{243}{1000}, the probability of exactly two of three packets being transferred successfully,
  • BinomialDist[3, 0.9, 3, false] yields \frac{729}{1000}, the probability of all three packets being transferred successfully.
  • BinomialDist[3, 0.9, 0, true] yields \frac{1}{1000}, the probability of none of the three packets being transferred successfully,
  • BinomialDist[3, 0.9, 1, true] yields \frac{7}{250}, the probability of at most one of three packets being transferred successfully,
  • BinomialDist[3, 0.9, 2, true] yields \frac{271}{1000}, the probability of at most two of three packets being transferred successfully,
  • BinomialDist[3, 0.9, 3, true] yields 1, the probability of at most three of three packets being transferred successfully.
  • BinomialDist[3, 0.9, 4, false] yields 0, the probability of exactly four of three packets being transferred successfully,
  • BinomialDist[3, 0.9, 4, true] yields 1, the probability of at most four of three packets being transferred successfully.
© 2024 International GeoGebra Institute