Difference between revisions of "TriangleCurve Command"
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{{Example|1=If ''P, Q, R'' are points, <code>TriangleCurve[P, Q, R, (A - B)*(B - C)*(C - A) = 0]</code> gives a cubic curve consisting of the medians of the triangle ''PQR''.}} | {{Example|1=If ''P, Q, R'' are points, <code>TriangleCurve[P, Q, R, (A - B)*(B - C)*(C - A) = 0]</code> gives a cubic curve consisting of the medians of the triangle ''PQR''.}} | ||
{{Example|1= | {{Example|1= | ||
− | <code>TriangleCurve[A, B, C, A*C = 1/8]</code> creates a hyperbola such that tangent through A to this hyperbola splits triangle ABC in two parts of equal area. | + | <code>TriangleCurve[A, B, C, A*C = 1/8]</code> creates a hyperbola such that tangent, through A or C, to this hyperbola splits triangle ABC in two parts of equal area. |
}} | }} | ||
{{Note|The input points can be called ''A'', ''B'' or ''C'', but in this case you cannot use e.g. ''x(A)'' in the equation, because ''A'' is interpreted as the barycentric coordinate.}} | {{Note|The input points can be called ''A'', ''B'' or ''C'', but in this case you cannot use e.g. ''x(A)'' in the equation, because ''A'' is interpreted as the barycentric coordinate.}} |
Revision as of 16:00, 26 August 2012
This page is about a feature that is supported only in GeoGebra 4.2. |
- TriangleCurve[<Point P>, <Point Q>, <Point R>, <Equation in A, B, C>]
- creates implicit polynomial, whose equation in barycentric coordinates with respect to points P, Q, R is given by the fourth parameter; the barycentric coordinates are referred to as A, B, C.
Example: If P, Q, R are points,
TriangleCurve[P, Q, R, (A - B)*(B - C)*(C - A) = 0]
gives a cubic curve consisting of the medians of the triangle PQR.Example:
TriangleCurve[A, B, C, A*C = 1/8]
creates a hyperbola such that tangent, through A or C, to this hyperbola splits triangle ABC in two parts of equal area.
Note: The input points can be called A, B or C, but in this case you cannot use e.g. x(A) in the equation, because A is interpreted as the barycentric coordinate.