Difference between revisions of "UnitPerpendicularVector Command"

From GeoGebra Manual
Jump to: navigation, search
Line 14: Line 14:
 
:Yields a perpendicular vector with length 1 of the given vector.
 
:Yields a perpendicular vector with length 1 of the given vector.
 
:{{example|1=<div><code><nowiki>UnitPerpendicularVector[(a, b)]</nowiki></code> yields (<math>\frac{-b}{\sqrt{a^{2} + b^{2}&#125;}</math>, <math>\frac{a}{\sqrt{a^{2} + b^{2}&#125;}</math>).</div>}}
 
:{{example|1=<div><code><nowiki>UnitPerpendicularVector[(a, b)]</nowiki></code> yields (<math>\frac{-b}{\sqrt{a^{2} + b^{2}&#125;}</math>, <math>\frac{a}{\sqrt{a^{2} + b^{2}&#125;}</math>).</div>}}
 +
 +
{{betamanual|version=5.0|
 +
;UnitOrthogonalVector[ <Plane> ]
 +
:Creates a unit vector orthogonal to the plane.
 +
}}

Revision as of 14:20, 21 July 2014



UnitPerpendicularVector[ <Line>]
Returns the perpendicular vector with length 1 of the given line.
Example:
UnitPerpendicularVector[3x + 4y = 5] yields \begin{pmatrix}0.6\\0.8\end{pmatrix}.
UnitPerpendicularVector[ <Segment> ]
Returns the perpendicular vector with length 1 of the given segment.
Example:
Let s = Segment[(1,1), (4,5)].
UnitPerpendicularVector[s] yields \begin{pmatrix}-0.8\\0.6\end{pmatrix}.
UnitPerpendicularVector[ <Vector> ]
Returns the perpendicular vector with length 1 of the given vector. The vector must be defined first.
Example:
Let v=\begin{pmatrix}3\\4\end{pmatrix}. UnitPerpendicularVector[v] yields \begin{pmatrix}-0.8\\0.6\end{pmatrix}.

CAS Syntax

UnitPerpendicularVector[ <Vector> ]
Yields a perpendicular vector with length 1 of the given vector.
Example:
UnitPerpendicularVector[(a, b)] yields (\frac{-b}{\sqrt{a^{2} + b^{2}}}, \frac{a}{\sqrt{a^{2} + b^{2}}}).


© 2024 International GeoGebra Institute