# Difference between revisions of "SolveODE Command"

##### Command Categories (All commands)

SolveODE[ <f'(x,y)>, <Start x>, <Start y>, <End x>, <Step> ]
Solves first order ordinary differential equations (ODE) \frac{dy}{dx}=f'(x,y) numerically given start point and end & step for x.
For example to solve \frac{dy}{dx}=-xy using A as a starting point, enter SolveOde[-x*y, x(A), y(A), 5, 0.1]
Note: Length[ <Locus> ] allows you to find out how many points are in the computed locus and First[ <Locus>, <Number> ] allows you to extract the points as a list, for example First[loc1, Length[loc1]]
SolveODE[ <f(x,y)>, <g(x,y)>, <Start x>, <Start y>, <End t>, <Step> ]
Solves first order ODE \frac{dy}{dx}=\frac{f(x,y)}{g(x,y)} given start point, maximal value of an internal parameter t and step for t. This version of the command may work where the first one fails eg when the solution curve has vertical points.
For example to solve \frac{dy}{dx}=- \frac{x}{y} using A as a starting point, enter SolveOde[-x, y, x(A), y(A), 5, 0.1]
SolveODE[ <b(x)>, <c(x)>, <f(x)>, <Start x>, <Start y>, <Start y'>, <End x>, <Step>]
Solves second order ODE y''+b(x)y'+c(x)y=f(x).
Note: Always returns the result as locus. The algorithms are based on Runge-Kutta numeric methods.

## CAS Syntax

Following two syntaxes work only in CAS View.

SolveODE(<f(x,y)>)
Attempts to find the exact solution of the first order ODE \frac{dy}{dx}=f(x,y).
SolveODE(<f( var1, var2)>, <var1>, <var2>)
Attempts to find the exact solution of the first order ODE \frac{dvar2}{dvar1}=f(var1,var2).
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