Difference between revisions of "ParseToFunction Command"

From GeoGebra Manual
Jump to: navigation, search
m
m (Text replace - ";(.*)\[(.*)\]" to ";$1($2)")
Line 1: Line 1:
 
<noinclude>{{Manual Page|version=5.0}}</noinclude>{{command|scripting}}
 
<noinclude>{{Manual Page|version=5.0}}</noinclude>{{command|scripting}}
;ParseToFunction[ <Function>, <String> ]
+
;ParseToFunction( <Function>, <String> )
 
:Parses the string and stores the result to a [[Functions|function]] ''f'', which must be defined and [[Free, Dependent and Auxiliary Objects|free]] before the command is used.
 
:Parses the string and stores the result to a [[Functions|function]] ''f'', which must be defined and [[Free, Dependent and Auxiliary Objects|free]] before the command is used.
 
:{{example|1=Define <code><nowiki> f(x) = 3x² + 2</nowiki></code> and <code><nowiki> text1 = "f(x) = 3x + 1"</nowiki></code>. <code><nowiki> ParseToFunction[f, text1]</nowiki></code> returns ''f(x) = 3x + 1''.}}
 
:{{example|1=Define <code><nowiki> f(x) = 3x² + 2</nowiki></code> and <code><nowiki> text1 = "f(x) = 3x + 1"</nowiki></code>. <code><nowiki> ParseToFunction[f, text1]</nowiki></code> returns ''f(x) = 3x + 1''.}}
 
{{note|1=See also [[ParseToNumber Command|ParseToNumber]] command. }}
 
{{note|1=See also [[ParseToNumber Command|ParseToNumber]] command. }}

Revision as of 17:17, 7 October 2017


ParseToFunction( <Function>, <String> )
Parses the string and stores the result to a function f, which must be defined and free before the command is used.
Example: Define f(x) = 3x² + 2 and text1 = "f(x) = 3x + 1". ParseToFunction[f, text1] returns f(x) = 3x + 1.
Note: See also ParseToNumber command.
© 2024 International GeoGebra Institute