Difference between revisions of "Invert Command"
From GeoGebra Manual
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\frac{-c}{a* d- b* c}& \frac{a}{ a* d- b* c} | \frac{-c}{a* d- b* c}& \frac{a}{ a* d- b* c} | ||
\end{pmatrix} | \end{pmatrix} | ||
− | </math> the inverse matrix of <math> | + | </math>, the inverse matrix of <math> |
\begin{pmatrix} | \begin{pmatrix} | ||
a & b\\ | a & b\\ | ||
Line 28: | Line 28: | ||
\end{pmatrix} | \end{pmatrix} | ||
</math>.</div>}} | </math>.</div>}} | ||
− | + | ;Invert[ <Function> ] | |
− | + | :Gives the inverse of the function. | |
− | : | + | :{{note|1=<div>The function must contain just one ''x'' and no account is taken of domain or range, for example for f(x)=x^2 or f(x) = sin(x). If there is more than one ''x'' in the function another command might help you:</div> |
− | {{ | + | ::{{example|1=<div>Both <code><nowiki>Invert[PartialFractions[(x + 1) / (x + 2)]]</nowiki></code> and <code><nowiki>Invert[CompleteSquare[x^2 + 2 x +1]]</nowiki></code> yield the inverse functions.</div>}}}} |
− | If there is more than one ''x'' in the function another command might help you: | ||
− | :{{example|1=<div><code><nowiki>Invert[PartialFractions[(x+1)/(x+2)]]</nowiki></code> | ||
− | |||
− | }} |
Revision as of 12:43, 17 September 2012
- Invert[ <Matrix> ]
- Inverts the given matrix.
- Example:
Invert[{{1, 2}, {3, 4}}]
yields\begin{pmatrix} -2 & 1\\ 1.5 & -0.5 \end{pmatrix} , the the inverse matrix of
\begin{pmatrix} 1 & 2\\ 3 & 4 \end{pmatrix}
.CAS Syntax
- Invert[ <Matrix> ]
- Inverts the given matrix.
- Example:
Invert[{{a, b}, {c, d}}]
yields\begin{pmatrix} \frac{d}{a* d- b* c} & \frac{-b}{a* d- b* c}\\ \frac{-c}{a* d- b* c}& \frac{a}{ a* d- b* c} \end{pmatrix} , the inverse matrix of
\begin{pmatrix} a & b\\ c & d \end{pmatrix}
.- Invert[ <Function> ]
- Gives the inverse of the function.
- Note:The function must contain just one x and no account is taken of domain or range, for example for f(x)=x^2 or f(x) = sin(x). If there is more than one x in the function another command might help you:
- Example:Both
Invert[PartialFractions[(x + 1) / (x + 2)]]
andInvert[CompleteSquare[x^2 + 2 x +1]]
yield the inverse functions.