Difference between revisions of "CurvatureVector Command"
From GeoGebra Manual
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:*<code><nowiki>CurvatureVector[(0, 0), Curve[cos(t), sin(2t), t, 0, π]]</nowiki></code> yields vector ''(0, 0)'' | :*<code><nowiki>CurvatureVector[(0, 0), Curve[cos(t), sin(2t), t, 0, π]]</nowiki></code> yields vector ''(0, 0)'' | ||
:*<code><nowiki>CurvatureVector[(-1, 0), Conic[{1, 1, 1, 2, 2, 3}]]</nowiki></code> yields vector ''(0, -2)''</div>}} | :*<code><nowiki>CurvatureVector[(-1, 0), Conic[{1, 1, 1, 2, 2, 3}]]</nowiki></code> yields vector ''(0, -2)''</div>}} | ||
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Revision as of 10:04, 29 July 2015
- CurvatureVector[ <Point>, <Function> ]
- Yields the curvature vector of the function in the given point.
- Example:
CurvatureVector[(0, 0), x^2]
yields vector (0, 2).
- CurvatureVector[ <Point>, <Curve> ]
- Yields the curvature vector of the curve in the given point.
- Example:
CurvatureVector[(0, 0), Curve[cos(t), sin(2t), t, 0, π]]
yields vector (0, 0).
- CurvatureVector[ <Point>, <Object> ]
- Yields the curvature vector of the object (function, curve, conic) in the given point.
- Examples:
CurvatureVector[(0, 0), x^2]
yields vector (0, 2)CurvatureVector[(0, 0), Curve[cos(t), sin(2t), t, 0, π]]
yields vector (0, 0)CurvatureVector[(-1, 0), Conic[{1, 1, 1, 2, 2, 3}]]
yields vector (0, -2)