Difference between revisions of "ConjugateDiameter Command"

From GeoGebra Manual
Jump to: navigation, search
(create official page from pdf)
m (Text replace - ";(.*)\[(.*)\]" to ";$1($2)")
 
(10 intermediate revisions by 6 users not shown)
Line 1: Line 1:
<noinclude>{{Manual Page}}[[Category:Manual (official)|{{PAGENAME}}]]</noinclude>
+
<noinclude>{{Manual Page|version=5.0}}</noinclude>{{command|conic}}
{{command|conic}}
+
;ConjugateDiameter( <Line>, <Conic> ):Returns the ([w:Conjugate diameters|conjugate diameter)] of the diameter that is parallel to the given line (relative to the conic section).
; ConjugateDiameter[Line, Conic]: Returns the conjugate diameter of the diameter that is parallel to the line (relative to the conic section).
+
:{{Example|1=<code>ConjugateDiameter(-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0)</code> yields line 5''x'' + 16''y'' = 11}}
; ConjugateDiameter[Vector, Conic]: Returns the conjugate diameter of the diameter that is parallel to the vector (relative to the conic section).
+
 
 +
; ConjugateDiameter( <Vector>, <Conic> ):Returns the ([w:Conjugate diameters|conjugate diameter)] of the diameter that is parallel to the given vector (relative to the conic section).
 +
:{{Example|1=Let ''u'' = (4,1) be a vector. Then <code>ConjugateDiameter(u, x^2 + 4 y^2 + 2x - 8y + 1 = 0)</code> yields line ''x'' + ''y'' = 0}}

Latest revision as of 17:15, 7 October 2017


ConjugateDiameter( <Line>, <Conic> )
Returns the ([w:Conjugate diameters|conjugate diameter)] of the diameter that is parallel to the given line (relative to the conic section).
Example: ConjugateDiameter(-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0) yields line 5x + 16y = 11


ConjugateDiameter( <Vector>, <Conic> )
Returns the ([w:Conjugate diameters|conjugate diameter)] of the diameter that is parallel to the given vector (relative to the conic section).
Example: Let u = (4,1) be a vector. Then ConjugateDiameter(u, x^2 + 4 y^2 + 2x - 8y + 1 = 0) yields line x + y = 0
© 2022 International GeoGebra Institute