Difference between revisions of "ConjugateDiameter Command"

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<noinclude>{{Manual Page|version=5.0}}</noinclude>{{command|conic}}
 
<noinclude>{{Manual Page|version=5.0}}</noinclude>{{command|conic}}
;ConjugateDiameter[ <Line>, <Conic> ]:Returns the [[w:Conjugate diameters|conjugate diameter]] of the diameter that is parallel to the given line (relative to the conic section).
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;ConjugateDiameter( <Line>, <Conic> ):Returns the [[w:Conjugate diameters|conjugate diameter]] of the diameter that is parallel to the given line (relative to the conic section).
:{{Example|1=<code>ConjugateDiameter[-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0]</code> yields line 5''x'' + 16''y'' = 11}}
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:{{Example|1=<code>ConjugateDiameter(-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0)</code> yields line 5''x'' + 16''y'' = 11}}
  
; ConjugateDiameter[ <Vector>, <Conic> ]:Returns the [[w:Conjugate diameters|conjugate diameter]] of the diameter that is parallel to the given vector (relative to the conic section).
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; ConjugateDiameter( <Vector>, <Conic> ):Returns the [[w:Conjugate diameters|conjugate diameter]] of the diameter that is parallel to the given vector (relative to the conic section).
:{{Example|1=Let ''u'' = (4,1) be a vector. Then <code>ConjugateDiameter[u, x^2 + 4 y^2 + 2x - 8y + 1 = 0]</code> yields line ''x'' + ''y'' = 0}}
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:{{Example|1=Let ''u'' = (4,1) be a vector. Then <code>ConjugateDiameter(u, x^2 + 4 y^2 + 2x - 8y + 1 = 0)</code> yields line ''x'' + ''y'' = 0}}

Revision as of 16:30, 4 October 2017


ConjugateDiameter( <Line>, <Conic> )
Returns the conjugate diameter of the diameter that is parallel to the given line (relative to the conic section).
Example: ConjugateDiameter(-4x + 5y = -2, x^2 + 4 y^2 + 2x - 8y + 1 = 0) yields line 5x + 16y = 11


ConjugateDiameter( <Vector>, <Conic> )
Returns the conjugate diameter of the diameter that is parallel to the given vector (relative to the conic section).
Example: Let u = (4,1) be a vector. Then ConjugateDiameter(u, x^2 + 4 y^2 + 2x - 8y + 1 = 0) yields line x + y = 0
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