BinomialDist Command
From GeoGebra Manual
Revision as of 09:43, 26 April 2013 by MagdalenaSophieF (talk | contribs)
- BinomialDist[ <Number of Trials>, <Probability of Success> ]
- Returns a bar graph of a Binomial distribution.
- The parameter Number of Trials specifies the number of independent Bernoulli trials and the parameter Probability of Success specifies the probability of success in one trial.
- BinomialDist[ <Number of Trials>, <Probability of Success>, <Boolean Cumulative> ]
- Returns a bar graph of a Binomial distribution when Cumulative = false.
- Returns a bar graph of a cumulative Binomial distribution when Cumulative = true.
- First two parameters are same as above.
- BinomialDist[ <Number of Trials>, <Probability of Success>, <Variable Value>, <Boolean Cumulative> ]
- Let X be a Binomial random variable and let v be the variable value.
- Returns P( X = v) when Cumulative = false.
- Returns P( X ≤ v) when Cumulative = true.
- First two parameters are same as above.
CAS Specific Syntax
In CAS View only one syntax is allowed:
- BinomialDist[ <Number of Trials>, <Probability of Success>, <Variable Value>, <Boolean Cumulative> ]
- Let X be a Binomial random variable and let v be the variable value.
- Returns P( X = v) when Cumulative = false.
- Returns P( X ≤ v) when Cumulative = true.
- Example:Assume transfering three packets of data over a faulty line. The chance an arbitrary packet transfered over this line becomes corrupted is \frac{1}{10}, hence the propability of transfering an arbitrary packet successfully is \frac{9}{10}.
BinomialDist[3, 0.9, 0, false]
yields \frac{1}{1000}, the probability of none of the three packets being transferred successfully,BinomialDist[3, 0.9, 1, false]
yields \frac{27}{1000}, the probability of exactly one of three packets being transferred successfully,BinomialDist[3, 0.9, 2, false]
yields \frac{243}{1000}, the probability of exactly two of three packets being transferred successfully,BinomialDist[3, 0.9, 3, false]
yields \frac{729}{1000}, the probability of all three packets being transferred successfully.BinomialDist[3, 0.9, 0, true]
yields \frac{1}{1000}, the probability of none of the three packets being transferred successfully,BinomialDist[3, 0.9, 1, true]
yields \frac{7}{250}, the probability of at most one of three packets being transferred successfully,BinomialDist[3, 0.9, 2, true]
yields \frac{271}{1000}, the probability of at most two of three packets being transferred successfully,BinomialDist[3, 0.9, 3, true]
yields 1, the probability of at most three of three packets being transferred successfully.BinomialDist[3, 0.9, 4, false]
yields 0, the probability of exactly four of three packets being transferred successfully,BinomialDist[3, 0.9, 4, true]
yields 1, the probability of at most four of three packets being transferred successfully.