Difference between revisions of "Assume Command"

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:*<code><nowiki>Assume(x>0 && n>0, Solve(log(n^2*(x/n)^lg(x))=log(x^2), x))</nowiki></code> yields <code>{x = 100, x = n}</code>
 
:*<code><nowiki>Assume(x>0 && n>0, Solve(log(n^2*(x/n)^lg(x))=log(x^2), x))</nowiki></code> yields <code>{x = 100, x = n}</code>
 
:*<code><nowiki>Assume(x<2,Simplify(sqrt(x-2sqrt(x-1))))</nowiki></code> yields <code>-sqrt(abs(x - 1)) + 1</code>
 
:*<code><nowiki>Assume(x<2,Simplify(sqrt(x-2sqrt(x-1))))</nowiki></code> yields <code>-sqrt(abs(x - 1)) + 1</code>
:*<code><nowiki>Assume(x>2,Simplify(sqrt(x-2sqrt(x-1))))</nowiki></code> yields <code>sqrt(abs(x - 1)) + 1</code></div>}}
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:*<code><nowiki>Assume(x>2,Simplify(sqrt(x-2sqrt(x-1))))</nowiki></code> yields <code>sqrt(x - 1) + 1</code></div>}}
  
  

Revision as of 21:28, 15 May 2019


CAS Syntax

Assume( <Condition>, <Expression> )
Evaluates the expression according to the condition
Examples:
  • Assume(a > 0, Integral(exp(-a x), 0, infinity)) yields 1 / a.
  • Assume(x>0 && n>0, Solve(log(n^2*(x/n)^lg(x))=log(x^2), x)) yields {x = 100, x = n}
  • Assume(x<2,Simplify(sqrt(x-2sqrt(x-1)))) yields -sqrt(abs(x - 1)) + 1
  • Assume(x>2,Simplify(sqrt(x-2sqrt(x-1)))) yields sqrt(x - 1) + 1




Note: See also Solve Command.
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