Difference between revisions of "AreEqual Command"
From GeoGebra Manual
m (typo) |
(Change for the next release: AreEqual[Segment[(1, 2), (3, 4)], Segment[(3, 4), (1, 6)]] is different from Segment[(1, 2), (3, 4)] == Segment[(3, 4), (1, 6)] as the latter just compares the lengths}}) |
||
Line 1: | Line 1: | ||
− | <noinclude>{{Manual Page|version=5.0}}</noinclude>{{command|logical | + | <noinclude>{{Manual Page|version=5.0}}</noinclude>{{command|logical}} |
;AreEqual[ <Object>, <Object> ] | ;AreEqual[ <Object>, <Object> ] | ||
:Decides if the objects are equal. | :Decides if the objects are equal. | ||
Normally this command computes the result numerically. This behavior can be changed by using the [[Prove Command|Prove]] command. | Normally this command computes the result numerically. This behavior can be changed by using the [[Prove Command|Prove]] command. | ||
− | :{{example| 1=<div><code><nowiki>AreEqual[ | + | :{{example| 1=<div><code><nowiki>AreEqual[Circle[(0, 0),1],x^2+y^2=1]</nowiki></code> yields ''true'' since the two circles have the same center and radius. </div>}} |
{{Note| See also [[AreCollinear Command|AreCollinear]], [[AreConcyclic Command|AreConcyclic]], [[AreConcurrent Command|AreConcurrent]], [[ArePerpendicular Command|ArePerpendicular]], [[AreParallel Command|AreParallel]] commands.}} | {{Note| See also [[AreCollinear Command|AreCollinear]], [[AreConcyclic Command|AreConcyclic]], [[AreConcurrent Command|AreConcurrent]], [[ArePerpendicular Command|ArePerpendicular]], [[AreParallel Command|AreParallel]] commands.}} | ||
+ | |||
+ | {{Note| <code><nowiki>AreEqual[Segment[(1, 2), (3, 4)], Segment[(3, 4), (1, 6)]]</nowiki></code> is different from <code><nowiki>Segment[(1, 2), (3, 4)] == Segment[(3, 4), (1, 6)]</nowiki></code> as the latter compares just the lengths}} |
Revision as of 09:17, 8 July 2015
- AreEqual[ <Object>, <Object> ]
- Decides if the objects are equal.
Normally this command computes the result numerically. This behavior can be changed by using the Prove command.
- Example:
AreEqual[Circle[(0, 0),1],x^2+y^2=1]
yields true since the two circles have the same center and radius.
Note: See also AreCollinear, AreConcyclic, AreConcurrent, ArePerpendicular, AreParallel commands.
Note:
AreEqual[Segment[(1, 2), (3, 4)], Segment[(3, 4), (1, 6)]]
is different from Segment[(1, 2), (3, 4)] == Segment[(3, 4), (1, 6)]
as the latter compares just the lengths